right, here is what I want / need to do:
I'm doing some simple kind of a news system atm and due having no sql at the webspace it has to be a bit "simple" (but also because of I know shit about sql databases and stuff
).
Anyway, my plan is to put all the news in different files like year.month.day.txt (070319.txt) and put them all in a directory. Now I want to read that directory, sort all files by date (therefore the filename) and echo them all on the newspage.
The news files look like this:
18.03.07<;>
News Title<;>
Description<;>
Newstext<;>
And my code I ended up is:
$tborder
=
0;
$twidth
=
"100%";
$cssheadline
=
"headline";
$cssdate
=
"date";
$csstext
=
"text";
$cnt
=
0;
$pfad
=
"content/news2/articles/";
function ls($dir)
{
$handle = opendir($dir);
for(;(false !== ($readdir = readdir($handle)));)
{
if($readdir != '.' && $readdir != '..')
{
$path = $dir.'/'.$readdir;
if(is_dir($path))
{
$output[$readdir] = ls($path);
}
if(is_file($path) && substr($path,-4) == '.txt')
{
$output[] = $readdir;
}
}
}
return isset($output)?$output:false;
closedir($handle);
}
$ary = ls($pfad);
arsort ($ary);
for ( $i = count($ary); $i >= 0; $i--)
{
$string = join("\n",file($pfad.$ary[$i])); // Description, Newstext can be over several lines and contain some html code
$content[$cnt] = explode("<;>", $string);
$len = count($content[$cnt]);
for ($j=0; $j<$len-1; $j++)
{
$content[$cnt][$j];
}
$cnt++;
}
// Augabe news.php
$ncnt
=
$cnt-1;
for ($i = 1; $i <= $ncnt; $i++)
{
echo
"<table border=\"".$tborder."\" width=\"".$twidth."\">\n";
echo
"<tr><td class=\"".$cssheadline."\">".$content[$i][1]."</td></tr>";
echo
"<tr><td class=\"".$cssdate."\">".$content[$i][0]."</td></tr>";
echo
"<tr><td class=\"".$csstext."\"><blockquote>".$content[$i][2]."</blockquote></td></tr>";
echo
"</table>\n";
echo
"<hr>";
}
Ok, now me being a php noob asks you in hope that you know more than me if there is a better way to do that stuff?
happy easter everyone 
.gif)
